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Q:
Why does GCC silently ignore unsafe constructors and destruction of my struct’s instance variables?
I have a struct that has a private, non-default-constructible member. I want to prevent accidental assignment (i.e., to restrict it to certain module-level functions that are given a pointer to an already-created instance).
I have a private member of my struct, which is used to prevent accidental assignment of a pre-existing instance:
struct Foo {
Foo() : bar(0) { }
Foo(const Foo&) = delete;
Foo& operator=(const Foo&) = delete;
int bar;
};
… which seems to work when I define no constructors, and don’t define a = delete. The constructor and copy operator are marked as deleted and therefore don’t get generated by the compiler.
BUT
If I define at least one of the two constructors, or define the copy assignment operator (without deleting it), the compiler generates all three constructors and the copy operator (gcc 4.8.1); so now the constructor and copy operator work as expected (I’d expect the compiler to generate no code when I define the destructor as well); also, when I define a = b, the compiler-generated copy constructor and copy assignment operator are replaced by the compiler-generated move constructor and move assignment operator.
However, the compiler seems to completely ignore the deleted functions: e.g. if I define something like
void foo() {
Foo f;
}
The compiler does not generate the constructor and the destructor.
So the questions are:
Why does the compiler not generate the constructor and destructor?
Why is it that when I delete the copy-constructor (or the copy-assignment operator), it removes the = delete (or overload) but not the default constructor? Why is the destructor not deleted in that case?
Can anyone point me to the relevant rules in the Standard that I
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