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$$\mathcal{A}_{\theta,0}=\left( \begin{array}{ccc}
\sin(\theta) & 0 & -\cos(\theta) \\
\sin(2\theta) & 0 & -\sin(2\theta) \\
\sin(3\theta) & 0 & -\cos(3\theta)
\end{array} \right)$$
SÃ, sÃ, sÃ, es del suyo el buen dÃa:
$$\mathcal{A}_\theta=\exp(\mathcal{A}_{\theta,0})=\left(\begin{array}{ccc}
\cos(\theta) & \sin(\theta) & 0 \\
-\sin(\theta) & \cos(\theta) & 0 \\
0 & 0 & 1
\end{array} \right)$$
Por la derecha se ve muy fácil, pero, curiosamente, a mi no me ve el cálculo (sin enterarme aun del significado del lÃo de otro sitio, asà que: para mÃ, digamos que es “simples”).
Tengo que pensar en una forma de encadenar los matices, porque si no, el cálculo resultarÃa bastante incomprensible para el mero semántico (cuando no me equivocé):
$$\mathcal{A}_{\theta}=\exp(\mathcal{A}_{\theta,0})=\left(\begin{array}{ccc}
\cos(\theta) & \sin(\theta) & 0 \\
-\sin(\theta) & \cos(\theta) & 0 \\
0 & 0 & 1
\end{array} \right)$$
$$\mathcal{A}_\theta=\left(\begin{array}{ccc}
\cos(\theta) & \sin(\theta) & 0 \\
-\sin(\
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