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Recursively call function based on argument
I am trying to define a function that makes another function call itself on an argument. For example,
myfunc(0)
>>> 1
myfunc(1)
>>> 2
myfunc(2)
>>> 3
I don’t need any additional arguments, just the optional one. How should I do this?
A:
You can solve this using recursion. Here’s a simple example:
def myfunc(i):
if i == 0:
return 1
else:
return myfunc(i – 1) + myfunc(i – 1)
print myfunc(5) # => 24
Note: your stated example has syntax errors, and since your questions concerns recursive functions, I’d expect to see a few more attempts to solve the problem that don’t work.
Q:
How does the definition of $\displaystyle\int_{0}^{0}\ln{\left|\frac{x}{a}\right|} dx$ change as $a \to 0$?
I am trying to find the derivative of the following function:
$$G(a) = \int_{0}^{0}\ln{\left|\frac{x}{a}\right|} dx.$$
The $x$-argument of the logarith
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